What are the roots of x2 + 10x + 29 = 0?

A. 5 ± 2i

B. - 5 ± 2i

C. 10 + 4i

D. - 10 + 4i

B

Step-by-step explanation:

okay so x^2+10x+29=0

subtract 29 from both sides giving you:

x^2+10=-29

next, used (b/2) ^2 to create a trinomial square, which will be 5 so you will have:

x^2-10x + (-5) ^2=-29 + (-5) ^2

Then, simplify the equation:

x^2-10x+25=-4

Next, factor into (x-5) ^2 which is:

(x-5) ^2 = - 4

Finally, solve for X:

x=5 + / - 2i

x2+10*+29=0

answer is A 5+2i