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28 February, 14:56

In triangle ABC, Aat the top of the triangle, B at 90° and C at the third end, angle C = 21°, the hypotenus = 15m, find BC = y the unknown side

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  1. 28 February, 16:23
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    Step-by-step explanation:

    Law of sines: SinB/15 = SinA/BC

    B = 90

    A = 180-90-21=69°

    BC = (15*SinA) / SinB = (15*sin69) / 1 ≈ 14m
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