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2 February, 15:04

Which of the following are roots of the polynomial function?

F (x) = x^3-x^2-5x-3

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Answers (2)
  1. 2 February, 17:08
    0
    Try this option:

    the function can be re-written in a form f (x) = (x+1) (x+1) (x-3);

    The roots of the function are 3 and - 1
  2. 2 February, 17:45
    0
    Answer with explanation:

    The given Polynomial function is:

    F (x) = x³-x²-5 x - 3

    By Rational root theorem, roots of the polynomial can be 1,-1, 3,-3.

    F (3) = 3³-3²-5*3-3

    =27-9-15-3

    = 0

    So, 3 is one of the root of the equation.

    That is, (x-3) will divide the whole polynomial.

    F (x) = x³-x²-5 x - 3

    = (x-3) (x²+2 x + 1)

    = (x-3) (x+1) ²

    to get the roots.

    1. x-3=0

    ⇒x=3

    2. (x+1) ²=0

    ⇒x+1=0

    ⇒x = - 1

    So, root of the polynomial function are=3, and,-1.

    Option B=3 and Option C = - 1
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