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22 March, 12:08

How do you solve 9^x=3^40?

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Answers (2)
  1. 22 March, 14:01
    0
    We have 9 = 3^2;

    Then, 9^x = (3^2) ^x = 3^ (2x);

    We solve 3^ (2x) = 3^40;

    2x = 40;

    x = 20 : 2;

    x = 10;
  2. 22 March, 14:36
    0
    Answer: x = 20

    Step-by-step explanation:

    Manipulate the bases so they are the same, then set the exponents equal to each other and solve for x:

    9ˣ = 3⁴⁰

    (3²) ˣ = 3⁴⁰

    3²ˣ = 3⁴⁰

    2x = 40

    x = 20
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