What value is a discontinuity of x^2 + 5x + 2 / x^2 + 2x - 35?

A. x = - 5

B. x = - 7

C. x = - 2

D. x = - 1

x equals - 7 and x equals 5 our function is discontinuous

Step-by-step explanation:

x^2+7x-5x-35=0

x (x+7) - 5 (x+7) = 0

(x+7) (x-5) = 0

(x+7) = 0/text{ or } (x-5) = 0

x=-7/text{ or }x=5