What are the factors of x2 - 49? (x - 1) (x + 49) (x - 7) (x - 7) (x - 7) (x + 7) Prime

the answer would be (x+7) (x-7)

(x+7) (x-7)

The factors are - 7 and 7

Step-by-step explanation:

Given the function x²-49, to find the factors, we will factorise the expressed using the different of two square.

If a and b are two numbers, then based on difference of two square;

a²-b² = (a+b) (a-b)

Applying this to the function in question

x²-49

= x²-7²

= (x+7) (x-7)

The factors can be gotten by equating the function to zero according to factor theorem.

(x+7) (x-7) = 0

x+7 = 0 and x-7 = 0

x = - 7 and 7