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29 October, 17:00

Two consecutive intergers have a sum of 79, find the intergers

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  1. 29 October, 18:46
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    The integers are 39 and 40.

    Step-by-step explanation:

    Let the smaller integer be x.

    The next greater integer is x + 1.

    Their sum is x + x + 1.

    Their sum is 79, so

    x + x + 1 = 79

    Solve for x.

    2x + 1 = 79

    2x = 78

    x = 39

    x + 1 = 40
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