The volume V, in cubic centimeters, of 1 kilogram of water at a temperature T (in Celsius) is given approximately by the formula V (T) = - 6.8 * 10 - 5 T 3 + 8.5 * 10 - 3 T 2 - 6.4 * 10 - 2 T + 9.99 * 10 2 where 0 C ≤ T ≤ 30 C. Find the temperature at which water has its minimum volume. Round your final answer to 2 decimal places.

Answer: V = 9990 cubic centimeter

Step-by-step explanation:

Given that the volume V in cubic centimeters, at a temperature T (in Celsius) is given approximately by the formula

V (T) = - 6.8 * 10 ^ - 5 T 3 + 8.5 * 10 - ^3 T 2 - 6.4 * 10 - ^2 T + 9.99 * 10^2 where 0 C ≤ T ≤ 30 C.

Water has its minimum volume at low temperature. That is T = 0

Therefore,

V (0) = - 6.8 * 10 - 5 (0) 3 + 8.5 * 10 - 3 (0) 2 - 6.4 * 10 - 2 (0) + 9.99 * 10^2

V (0) = 99.9 * 100

V (0) = 9990 cubic centimeter