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15 January, 10:59

the length of a rectangle is four times its width. If the area of the rectangle is 400yd^2, find its perimeter.

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  1. 15 January, 12:21
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    100yd

    Step-by-step explanation:

    Let the width of the rectangle be x yd

    Length will be 4x yd

    Area = Length * width

    400yd² = 4x (x)

    4x² = 400yd²

    Dividing by 4 throughout gives;

    x² = 100, x = 10yd

    So x (width) = 10yd

    Length = 4 (10) = 40yd

    Perimeter = 2 (length + width)

    Perimeter = 2 (40 + 10) = 2 (50) 100yd
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