What is the vertex of the quadratic function fix = (x-8) (x-2)

Question

Mathematics

Trevin Patel

22 April, 01:54

What is the vertex of the quadratic function fix = (x-8) (x-2)

+3

Answers (1)

Know the Answer?

Kaiden Aguirre · Answer 1

Vertex: (5, - 9)

Step-by-step explanation:

fix = (x-8) (x-2)

fix = x^2 - 2x - 8x + 16

fix = x^2 - 10x + 16

a = 1, b = - 10, and c = 16

To find vertex:

x = - b/2a

x = - (-10) / 2 (1)

x = 10/2

x = 5

y = 5^2 - 10 (5) + 16

y = 25 - 50 + 16

y = - 9

Vertex: (5, - 9)