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11 January, 17:00

Which sum or difference identity could be used to prove that sin (pi+q) = -sinq

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  1. 11 January, 19:03
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    see explanation

    Step-by-step explanation:

    Using the Addition formula for sine

    sin (x + y) = sinxcosy + cosxsiny

    and sinπ = 0, cosπ = - 1, then

    sin (π + q)

    = sinπcosq + cosπsinq

    = 0. cosq + ( - 1) sinq

    = 0 - sinq

    = - sinq ← as required
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