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27 June, 10:38

Write a polynomial function of least degree with integral coefficients that has the given zeros. 4, - 6, 1

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  1. 27 June, 13:11
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    Answer: f (x) = x³ + x² - 26x + 24

    Step-by-step explanation:

    x = 4 x = - 6 x = 1

    x - 4 = 0 x + 6 = 0 x - 1 = 0

    (x - 4) (x + 6) (x - 1) = 0

    (x² + 2x - 24) (x - 1) = 0

    x (x² + 2x - 24) - 1 (x² + 2x - 24) = 0

    x³ + 2x² - 24x - x² - 2x + 24 = 0

    x³ + x² - 26x + 24 = 0
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