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24 October, 22:40

What is the vertex form of 4x^2+4x-12

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Answers (2)
  1. 24 October, 23:15
    0
    (-1/2, - 13/4)

    Step-by-step explanation:

    Start with y = 4x^2+4x-12. Put this into the form y = a (x-h) ^2 + k, where (h, k) represents the vertex.

    Factor 4 out of this expression, obtaining: y = 4 (x^2 + x - 3).

    Next, complete the square of the quantity inside parentheses:

    y = 4[ x^2 + x + 1/4 - 1/4 - 3 ], or

    y = 4[ (x + 1/2) ^2 - 13/4 ]

    We can now conclude that the vertex is (-1/2, - 13/4).
  2. 25 October, 02:22
    0
    (-0.5, - 13)
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