The line of symmetry of the parabola whose equation is y = ax2 - 4x + 3 is x = - 2. What is the value of "a"? - 2 - 1 - 1/2

a = - 1.

Step-by-step explanation:

y = ax^2 - 4x + 3

Convert to vertex form:-

= a (x^2 - 4/a) + 3

= a [ (x - 2/a) ^2 - 4/a^2 ] + 3

From this we see that the line of symmetry is y = 2/a so

2/a = - 2

-2a = 2

a = - 1.