Ask Question
19 August, 20:06

How do you " find, to the nearest tenth of an inch, the diagonal of a square whose perimeter is 28 inches?"

+1
Answers (1)
  1. 19 August, 22:05
    0
    Well if the perimeter is 28 inches, each side of the square is 7 inches. 28/4 = 7 because all sides of a square are the same.

    If we split the square in half to create 2 triangles we can find the length of the diagonal. The two sides are the bases of 7 inches.

    Use the Pythagorean theorem to solve for the hypotenuse or the diagonal.

    7^2 + 7^2 = diagonal ^ 2

    Therefore, the diagonal equals 9.9 inches.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How do you " find, to the nearest tenth of an inch, the diagonal of a square whose perimeter is 28 inches?" ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers