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18 July, 14:41

What is the equation of the quadratic function in vertex form if the vertex is at (3,5) and has a leading coefficient of 2

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Answers (2)
  1. 18 July, 16:51
    0
    y = 2 (x - 3) ² + 5

    Step-by-step explanation:

    the equation of a parabola in vertex form is

    y = a (x - h) ² + k

    where (h, k) are the coordinates of the vertex and a is a multiplier

    here (h, k) = (3, 5) and a = 2, hence

    y = 2 (x - 3) ² + 5 ← in vertex form
  2. 18 July, 18:12
    0
    y-5 = 2 (x-3) ^2

    Step-by-step explanation:

    The general form of this quadratic equation is y-k = a (x-h), where (h, k) is the vertex and a is the leading coefficient.

    In this case, y-5 = 2 (x-3) ^2.
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