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3 May, 23:42

A set of score has a mean of μ = 63 and a standard deviation of σ = 8. if these scores are standardized so that the new distribution has μ = 50 and σ = 10, what new value would be obtained for a score of x = 59 from the original distribution?

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  1. 4 May, 02:54
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    The z-score of 59 in the original distribution is

    z = (59 - 63) / 8 = - 1/2

    The corresponding x-score in the new distribution is

    -1/2 = (x - 50) / 10

    -5 = x - 50

    45 = x

    The new value of 45 would be obtained for a score of 59 from the original distribution.
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