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11 March, 07:35

Find the solution to the equation below. 2x^2+3x-20=0

A. x = - 4, - 3/2

B. x = - 4, 3/2

C. x = - 5/2, 4

D. x = - 4, 5/2

+5
Answers (2)
  1. 11 March, 08:36
    0
    The right choice is (D) x = - 4, 5/2

    Step-by-step explanation:

    2x^2+3x-20=0

    By factoring the expression we get

    2x²2 + 8x-5x-20=0

    (x+4) (2x-5) = 0

    Now

    (x+4) = 0 OR x = - 4

    and

    (2x-5) = 0 OR x = 5/2

    S the solutions are

    x = - 4 and x = 5/2
  2. 11 March, 09:17
    0
    C maybe bro I'm not really sure tho think I'm messing up
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