the surface areas of two similar solids are 441 cm² if the volume of the smaller solid is 250 cm³ what is the volume of the larger solid to the nearest cubic centimeter

The complete question is;

The surface areas of two similar solids are 441 cm² and 225 cm². If the volume of the smaller solid is 250 cm³ what is the volume of the larger solid to the nearest cubic centimeter

Answer:

volume of the larger solid; V = 686 cm³

Step-by-step explanation:

We are given that;

Area of smaller solid = 225 cm²

Area of bigger solid = 441 cm²

Now, let r be the ratio of similarity;

Thus ratio of big to small solid is gotten from;

441 = 225 x r²

441/225 = r²

r = √441/225

r = 21/15 = 7/5

Now, let V be the volume of the larger solid.

Thus;

V = r³ (250)

V = (7/5) ³ (250)

V = 686 cm³