Ask Question
17 January, 01:05

A hyperbola centered at the origin has vertices at (± √33,0) and foci at (± √59,0).

Write the equation of this hyperbola.

+1
Answers (1)
  1. 17 January, 04:43
    0
    x^2/33 + y^2/26 = 1

    Step-by-step explanation:

    The formula for a hyperbola centered at the origin is:

    x^2/a^2 - y^2/b^2 = 1

    The vertices are located at (±a, 0), so we have that the value of a is √33

    The foci are located at (±c, 0), where c^2 = a^2 + b^2

    So if we have that c = √59, we can find the value of b:

    59 = 33 + b^2

    b^2 = 26

    b = √26

    So the formula for this hyperbole is:

    x^2/33 + y^2/26 = 1
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A hyperbola centered at the origin has vertices at (± √33,0) and foci at (± √59,0). Write the equation of this hyperbola. ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers