Evaluate the summation of 25 times 0.3 to the n plus 1 power, from n equals 2 to 10.

a1=25 (0.3) ^2, common ratio = 0.3

So sum of first n terms of a geometric series = a1 (1-r^n) / (1-r)

So sum of frist 10 terms of the given series = 25 (0.3) ^2 (1-0.3^10) / (1-0.3)

So sum of n=2 to n=10 is : 25 (0.3) ^2 (1=0.3^10) / (1-0.3) - 25 (0.3) ^2 = 0.96426673425