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31 July, 19:56

The magnitude, M, of an earthquake is defined to be M=log I/S, where I is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and S is the intensity of a "standard" earthquake, which is barely detectable. What is the magnitude of an earthquake that is 35 times more intense than a standard earthquake? Use a calculator. Round your answer to the nearest tenth.

-1.5?

-0.5?

1.5?

3.6?

+1
Answers (1)
  1. 31 July, 23:47
    0
    Given:

    M = log I/S

    M = magnitude

    I = intensity of the earthquake

    S = intensity of the standard earthquake

    The minimum intensity of a standard earthquake is 10.

    Intensity of the earthquake is 35 times the standard earthquake. So,

    10 x 35 = 350

    M = log 350/10

    M = log 35

    M = 1.544 or 1.5 Third option
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