The square of a positive number increased by twice the number equals three. Find the number

1

Step-by-step explanation:

Let the number be x

x² + 2x = 3

x² + 2x - 3 = 0

Product = - 3

Sum = 2

Factors = 3 * (-1)

x² + 3x - x - 3 = 0

x * (x+3) - (x + 3) = 0

(x + 3) (x - 1) = 0

Ignore x + 3 because the number is a positive number

x - 1 = 0

x = 1

The number is 1