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Bronson Alexander
7 February, 04:33
How do I complete this factor? 16x^2-18=
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Francis
7 February, 06:50
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To factor 16x^2-18, recognize that this could be regarded as the difference of two squares: 16x^2-18 = (4x) ^2 - (√18) ^2.
Follow this pattern for the difference of two squares: a^2 - b^2 = (a - b) (a + b)
Thus, (4x) ^2 - (√18) ^2 = (4x + √18) (4x - √18)
Note that √18 can be reduced to 3√2.
Therefore, the factors in simplest form are (4x + 3√2) and (4x - 3√2).
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