Suppose a normal distribution has a mean of 98 and a standard deviation of 6. What is P (x< or = to 110)

97.8%

Step-by-step explanation:

110 is 2 standard deviations above the mean (6+6 = 12)

12+98 = 110

Looking at the standard deviation curve

P (x110)

We can find the probability that x>100 by adding anything above 2 standard deviations above the curve.

P (x>110) = 2.1+.1 = 2.2%

P (x110)

= 1 - 2.2%

= 1-.022

=.978

= 97.8 %