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4 January, 22:31

Identify the vertex and axis of symmetry of the function f (x) = - (x + 1) ^2 + 2 *

x = - 1; (-1, 2)

x = 1; (1, 2)

x = - 2; (2, - 1)

x = 2; (2, 1)

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  1. 4 January, 23:24
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    x = - 1; (-1, 2)

    Step-by-step explanation:

    f (x) = - (x + 1) ^2 + 2

    This is in vertex form

    y = a (x-h) ^2 + k where the vertex is (h, k) and the axis of symmetry is x=h

    f (x) = - (x - - 1) ^2 + 2

    Axis of symmetry is x=-1

    Vertex is (-1,2)
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