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14 July, 21:35

Factor the expression over the complex numbers. x2+18 Enter your answer in the box.

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Answers (2)
  1. 14 July, 22:23
    0
    (x - 3i√2) (x + 3i√2)

    solve x² + 18 = 0

    x² = - 18 ⇒ x = ±√ - 18 = ±3i√2

    factors are (x - (3i√2)) (x - (-3i√2))

    x² + 18 = (x - 3i√2) (x + 3i√2)
  2. 15 July, 00:18
    0
    Factor of the expression x²+18 over the complex numbers is:

    (x-i3√2) (x+i3√2)

    Step-by-step explanation:

    x²+18=0

    ⇒ x² = - 18

    ⇒ x=±√ (-18)

    ⇒ x=±i3√2

    ⇒ (x-i3√2) (x+i3√2) = 0

    Hence, factor of the expression x²+18 over the complex numbers is:

    (x-i3√2) (x+i3√2)
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