what is the cost of a new trampoline cover that needs to cover a trampoline with a diameter of 8 feet if the material cost 6.75 per square foot?

Answer: The cost of the trampoline cover would be $339.12

Step-by-step explanation: The radius of the trampoline is 4 feet (Diameter divided by 2 equals radius).

The trampoline cover will effectively cover the entire area of the trampoline and the area is given as

Area of circle = πr²

Area of circle = 3.14 x 4²

Area of circle = 3.14 x 16

Area of circle = 50.24 square foot

However the material costs $6.75 per square foot, which means the total cost of the trampoline cover would be derived as

Total area x cost per square foot = cost of trampoline cover

50.24 x 6.75 = Cost of trampoline cover

$339.12 = Cost of trampoline cover

Answer: The cost of the new trampoline cover is $339.29

Step-by-step explanation:

Hi, we have to calculate the area of the trampoline cover.

Since it has a circle form with a 8 ft diameter.

Area of a circle = π r^2

Since the radius (r) is equal to the diameter (d) divided by 2

R = d/2 = 8/2 = 4

Replacing in the formula:

A = π 4^2 = 50.26 square ft

Since the material cost 6.75 per square foot

Cost = 6.75 x 50.26 = $339.29