How do you solve:

3 (a+2) = 2 (a-7) and 9 (t-1) = 6 (t+2) - t

There are many many steps, but the answer is t=3

t=3

Step-by-step explanation:

Simplifying

5 + - 1 (t + 3) = - 1 + 2 (t + - 3) Reorder the terms:

5 + - 1 (3 + t) = - 1 + 2 (t + - 3)

5 + (3 * - 1 + t * - 1) = - 1 + 2 (t + - 3)

5 + (-3 + - 1t) = - 1 + 2 (t + - 3)

Combine like terms: 5 + - 3 = 2

2 + - 1t = - 1 + 2 (t + - 3)

Reorder the terms:

2 + - 1t = - 1 + 2 (-3 + t)

2 + - 1t = - 1 + (-3 * 2 + t * 2)

2 + - 1t = - 1 + (-6 + 2t)

Combine like terms: - 1 + - 6 = - 7

2 + - 1t = - 7 + 2t

Solving

2 + - 1t = - 7 + 2t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2t' to each side of the equation.

2 + - 1t + - 2t = - 7 + 2t + - 2t

Combine like terms: - 1t + - 2t = - 3t

2 + - 3t = - 7 + 2t + - 2t

Combine like terms: 2t + - 2t = 0

2 + - 3t = - 7 + 0

2 + - 3t = - 7

Add '-2' to each side of the equation.

2 + - 2 + - 3t = - 7 + - 2

Combine like terms: 2 + - 2 = 0

0 + - 3t = - 7 + - 2

-3t = - 7 + - 2

Combine like terms: - 7 + - 2 = - 9

-3t = - 9

Divide each side by '-3'.

t = 3

Simplifying

t = 3