Which is the approximate solution for the system of equations x+5y=10 and 3x+y=1?

Answer: The approximate solution is (-0.36, 2.08).

Step-by-step explanation:

Given system of equations:

x+5y=10 and 3x+y=1.

Let us solve the system of equation by substitution.

Solving second equation 3x+y=1 for y first.

3x+y=1.

Subtracting 3x from both sides, we get

3x-3x+y=1-3x

y = 1-3x.

Substituting y=1-3x in first equation x+5y=10, we get

x + 5 (1-3x) = 10.

x + 5 - 15x = 10

-14x + 5 = 10.

Subtracting 5 from both sides, we get

-14x + 5-5 = 10-5

-14x = 5

Dividing by - 14 on both sides, we get

-14x/-14=5/-14

x = - 0.36.

Plugging x=-0.36 in second equation y=1-3x, we get

y = 1-3 (-0.36) = 1+1.08 = 2.08.

Therefore, approximate solution is (-0.36, 2.08).

A (-0.3, 2.1)