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21 May, 19:35

Select the correct answer. If f (x) = x^3-x, what is the average rate of change of f (x) over the interval [1, 5]?

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  1. 21 May, 23:01
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    Average rate of change = 30

    Step-by-step explanation:

    We have given a function.

    f (x) = x³-x

    [a, b] = [1,5]

    We have to calculate the average rate of change of f (x) over the given interval.

    The formula to calculate the average rate of change of function is:

    Average rate of change = f (b) - f (a) / (b-a)

    f (b) = f (5) = (5) ³-5

    f (b) = f (5) = 125-5

    f (b) = f (5) = 120

    f (a) = f (1) = (1) ³-1

    f (a) = f (1) = 1-1

    f (a) = f (1) = 0

    Putting values in formula, we have

    Average rate of change = 120-0 / 5-1

    Average rate of change = 120/4

    Average rate of change = 30 which is the answer.
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