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29 January, 04:06

What are the vertex and x-intercepts of the graph of the function below?

y = x^2 - 6x-7

A. Vertex: (3,-16); Intercepts: x = 1, - 7

B. Vertex: (3, - 16); Intercepts: x=-1,7

C. Vertex: (3,-2); Intercepts: x = - 1,7

D. Vertex: (3,-2); Intercepts: x = 1, - 7

+1
Answers (1)
  1. 29 January, 06:21
    0
    y = x^2 - 6x-7

    Vertex = - b / 2a

    b = - 6

    a = 1

    - (-6) / 2 (1) = 3

    x = 3

    Use the substitution method to find y

    y = (3) ^2-6 (3) - 7

    (3) (3) - 18-7

    9-25

    y = - 16

    Vertex is (3, 16)

    Find x - intercept (y = 0)

    y = x^2 - 6x-7

    (x-7) (x+1)

    x-7 = 0

    Move - 7 to the other side. Sign changes from - 7 to 7

    x-7+7 = 0+7

    x = 7

    x+1 = 0

    Move + 1 to the other side. Sign changes from + 1 to - 1

    x+1-1 = 0-1

    x = - 1

    Answer : B. Vertex: (3, - 16); Intercepts: x=-1,7
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