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4 September, 02:31

Find the general indefinite integral. (use c for the constant of integration.) (1 - t) (9 + t2) dt

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  1. 4 September, 05:58
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    This is most easily done using the expanded form of the expression.

    ∫ (9 - 9t + t² - t³) dt = 9t - (9/2) t² + (1/3) t³ - (1/4) t⁴ + c
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