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28 April, 23:54

Select all that apply.

Solve for x, 0 < x < 360. 1/sin^2x = 4

answer choices (choose all that apply)

30

150

210

330

+3
Answers (1)
  1. 29 April, 03:20
    0
    30,150, 210,330

    Step-by-step explanation:

    1/sin^2x = 4

    Multiply each side by sin^2x

    1 = 4 sin^2 x

    Divide each side by 4

    1/4 = sin^2 x

    Take the square root of each side

    sqrt (1/4) = sqrt (sin^2 x)

    ±sqrt (1/4) = sin x

    ±1/2 = sinx

    Take the inverse sin of each side

    arcsin (1/2) = arcsin (sin x) and arcsin (-1/2) = arcsin (sin x)

    30 = x - 30 = x

    But this is not between 0 and 360,

    so we add 360

    -30+360 = 330

    We also have to look at the other locations where sin x = 1/2

    Taking the arcsin only gives values between - 90 and 90

    Since we are looking at the sin value, we take 180 - the value given

    180 - 30 = 150

    180 - -30

    180+30 = 210

    So our values are 30, 150,210,330
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