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22 June, 03:14

find the probability of having 2,3, or 4 successes in five trials of a binomial experiment in which the probability of success is 40%. round to the nearest tenth of a percent.

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  1. 22 June, 03:20
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    Let p be the probability of success, p = 0.4.

    Pr[2 success] = nC2 * p^2 * (1-p) ^3 = 0.346

    Pr[3 success] = nC3 * p^3 * (1-p) ^2 = 0.230

    Pr[4 success] = nC4 * p^4 * (1-p) ^1 = 0.077

    So, the probability of getting 2, 3, or 4 success, would be 0.356 + 0.230 + 0.077 = 0.663, alternatively, 66.3%.
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