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8 October, 13:40

Find two numbers, if their sum is 49 and their difference is 1/2

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  1. 8 October, 15:02
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    Let the two numbers be x and y respectively

    CaseI

    x+y=49

    or, x=49-y

    Case II

    x-y=1/2

    or, 49-y-y=1/2 (from case I)

    or, 49-2y=1/2

    or, 49-1/2=2y

    or, (49*2-1) / 2=2y

    or, 97/2=2y

    or, 48.5=2y

    or, 48.5/2=y

    Y=24.25

    Now,

    X=49-y

    or, x=49-24.25

    X=24.75
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