The first-, and second-year enrollment values for a technical school are shown in the table below:
Enrollment at a Technical School
Year (x)
First Year f (x)
Second Year t (x)
2009
756
756
2010
785
740
2011
710
781
2012
732
710
2013
755
800
Which of the following statements is true based on the data in the table?
The solution to s (x) = t (x) is x = 781.
The solution to s (x) = t (x) is x = 2011.
The solution to s (x) = t (x) is x = 756.
The solution to s (x) = t (x) is x = 2009.
Answers (1)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The first-, and second-year enrollment values for a technical school are shown in the table below: Enrollment at a Technical School Year ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers
You Might be Interested in
Find the average of 60 75 88 and 93
Answers (1)
What is 2 5/8 as a decimal
Answers (2)
Trevor season 8 red birds. He sees 5 more red birds than bluebirds. How many bluebirds does Trevor see?
Answers (1)
In f (x) = a|x - h| + k is a the slope? what's the y-intercept?
Answers (1)
What is 5 times 10 to the fifth?
Answers (2)
New Questions in Mathematics
Daniel is six feet tall and casts a shadow of 3.5 feet long. If his daughter is four feet tall, how long will her shadow be? a) 1.9 b) 5.3 c) 2.3 (the 3 has a line - above it btw) d) 4.5
Answers (1)
Which is the approximate solution to the system y = 0.5x + 3.5 and y = - x + shown on the graph? (-2.7, 2.1) (-2.1, 2.7) (2.1, 2.7) (2.7, 2.1)
Answers (2)
Julie is sewing the costumes for the school play. She needs to make fifteen bows. Each bow uses 3/4 of a yard of ribbon. Julie has 9 yards of ribbon. Does she have enough ribbon for the costumes?
Answers (1)
How do I describe the shape of a histogram?
Answers (1)
Jerry measured and timed the descent of a diving bell spider in a large fish tank. The spider reached a position 412 412 inches below the surface of the water after descending at a constant rate for 112 112 seconds.
Answers (1)