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10 June, 21:40

A nuclear power plant has two independent safety systems. The probability the first will not operate properly in an emergency P (A) is 0.01, and the probability the second will not operate P (B) in an emergency is 0.03. What is the probability that in an emergency both of the safety systems will not operate?

A. 3

B. 0.03

C. 0.0003

D. None of the choices are correct

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Answers (2)
  1. 10 June, 22:22
    0
    The systems are independent and function independently. The joint probability in question is 0.01*0.03 = 0.0003.
  2. 11 June, 01:16
    0
    Each system is independent of one another, so you multiply the probabilities of failure for each

    P (A and B) = P (A) * P (B)

    P (A and B) = 0.01*0.03

    P (A and B) = 0.0003

    Answer: Choice C
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