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13 October, 19:05

the first and last terms of a geometric progression are 2 and 2048 respectively. the sum of the series is 2730. find the number of terms and the common ratio

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  1. 13 October, 22:17
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    n=6

    Step-by-step explanation:

    Sn = (g1-gn. r) / (1-r)

    2730 = (2-2948r) / (1-r)

    2730 (1-r) = 2-2048r

    2730-2730r=2 - 2048r

    682r=2729

    r=4, common ratio

    Now using the formula; Gn=G1. r∧n-1

    2048=2.4∧n-1

    2048=4∧n-1=2∧2n-2

    ㏒2 1024=㏒2 2∧2n-2

    10=2n-2

    n=12/2

    =6
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