What values are solutions of 0 = 2xexponent of 2 - 6x-8

x = - 1 and x = 4

Step-by-step explanation:

Firstly solve the quadratic expression of

2x^2-6x-8 = 0 ... it gives you the two brackets of ... (2x-8) (x+1) = 0

then ... you equate the two brackets to 0. separately

2x-8 = 0 ... which gives you ... x = 4 ... as the first solution ... then ...;

x+1 = 0 ... which gives you ... x = - 1 ... as the second solution