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25 December, 00:36

The area of a rectangular fountain is x2 + 9x + 20 square feet. A 3-foot walkway is built around the fountain. Find the dimensions of the outside border of the walkway. The dimensions of the outside border of the walkway are

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  1. 25 December, 03:58
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    (x+11) by (x+10)

    Step-by-step explanation:

    We know that Area = Length x width

    Given: Area = x²+9x+20

    Lets sort this out first

    Area = x²+5x + 4x + 20

    Area = x (x+5) + 4 (x+5)

    Area = (x+5) (x+4)

    Therefore, it is concluded that:

    Length 'l' = (x+5) feet

    Width 'w' = (x+4) feet

    if a 3-foot walkway is built around the fountain, we'll add 3 feet on both sides

    Therefore,

    Outer Length = (x+5+3+3) = (x+11) feet

    Outer Width = (x+4+3+3) = (x+10) feet

    Answer:

    The fountain is (x+5) by (x+4).

    dimensions of the outside border of the walkway are (x+11) by (x+10)
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