What is the 8th term in a geometric sequence where the first term is equal to 4 and the common ration is 2?

512

Step-by-step explanation:

1st term = a

common ratio = r

a*r with the exponent n-1

a=4 r=2 n=8

8th term 4 * (2 at the seventh power) = 512

OR

1st term : 4

2nd term = 4*2=8

3rd term 8*2=16

4th term 12*2=32 ... 8th term 256*2=512