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26 October, 15:03

Mariana averaged 72 on her first three history exams. The first score was 78. The second score was 6 less than the third score. What did she score on the second and third exams?

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  1. 26 October, 15:25
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    F multiply both sides by 3, combine like terms

    93 - 44 + x + x = 3 (83)

    49 + 2x = 249

    2x = 249 - 49

    2x = 200

    x = 100 her score on the 3rd exam

    then

    100 - 44 = 56 on the 2nd exam

    :

    ;

    Check

    %2893%2B56%2B100%29%2F3 = 83
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