Seven slips of paper marked with the numbers 1, 2, 3, 4, 5, 6, and 7 are placed in a box and mixed well. Two are drawn.

What are the odds in favor of the sum of the numbers on the two selected slips is not 5?

Question

Alana Patrick

12 August, 14:03

+1

Answers (1)

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Killian Barrera · Answer 1

Total number = (6+5+4+3+2+1) * 2 = 42

Sums that equal 5 are 1,4 4,1 2,3 3,2

so you get 4/42 = 2/21

Seven slips of paper marked with the numbers 1, 2, 3, 4, 5, 6, and 7 are placed in a box and mixed well. Two are drawn.What are the odds in favor of the sum of the numbers on the two selected slips is not 5?