The R. R. Bowker Company of New York collects data on annual subscription rates to periodicals. Results are published in Library Journal. In a recent independent study, it was found that 63% of all students at Mill University read Time magazine, 51% read U. S. News and World Report, and 24% read both magazines. If a student at Mill University is randomly selected, what is the probability that the student reads either the Time magazine or the U. S. News and World Report magazine?

90%

Step-by-step explanation:

Let's call the percentage of students that read Time magazine by P (T), and the percentage of students that read U. S News and World Report by P (U). So, we have that:

P (T) = 0.63

P (U) = 0.51

P (T and U) = 0.24

To find the percentage of students that read either the Time magazine or the U. S. News and World Report magazine (that is, P (T or U)), we can use this formula:

P (T or U) = P (T) + P (U) - P (T and U)

So, we have that:

P (T or U) = 0.63 + 0.51 - 0.24 = 0.90

So the probability is 90%