A hyperbola centered at the origin has vertices at (0,±/sqrt (54) and foci at (0,±/sqrt (89)

Write the equation of this hyperbola

answer:The equation has the form y2a2-x2b2=1 y 2 a 2 - x 2 b 2 = 1, so the transverse axis lies on the y-axis. The hyperbola is centered at the origin, so the vertices serve as the y-intercepts of the graph. To find the vertices, set x=0 x = 0, and solve for y y.