Adult tickets to a basketball game cost $5. Student tickets cost $1. A total of $2,285 was collected on the

sale of 1,025 tickets. How many of each type of ticket were sold?

X=student tickets, y=adult tickets

x+y=1025

x+5y=2285

This system of equations can be solved through substitution.

x=1025-y

(1025-y) + 5y=2285

4y=1260

y=315

So, 315 adult tickets were sold.

315+x=1025

x=710

Therefore, 710 student tickets and 315 adult tickets were sold.

315 adults and 710 students

Step-by-step explanation:

x: no. of adults

y: no. of students

x + y = 1025

y = 1025 - x

5x + y = 2285

5x + 1025 - x = 2285

4x = 1260

x = 315

y = 1025 - 315 = 710