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1 April, 09:46

In a recent poll, 44 % of survey respondents said that, if they only had one child, they would prefer the child to be a boy. Suppose you conducted a survey of 150 randomly selected students on your campus and find that 71 of them would prefer a boy.

(a) Use the normal approximation to the binomial to approximate the probability that, in a random sample of 150 students, at least 71 would prefer a boy, assuming the true percentage is 44 %.

(b) Does this result contradict the poll? Explain.

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  1. 1 April, 12:01
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    a) The probability that 71 of 150 will prefer boy child is 71/150 or 0.47

    b) The result contradicts the poll actual percentage is 47.33% which is 3.33% more than the poll predicted

    Step-by-step explanation:

    If 71 out of 150 prefer boy child

    The probability that the 71 will prefer boy child is

    = 71/150

    The actual percentage is

    (71/150) * 100%

    = 47.33%

    This contradicts the poll as this is more than the poll predicted. That means Less than 71 of 150 actually preferred boy child.
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