The second of three numbers is 6 more than the first. The third number is twice the first. The sum of the three number is 26. Find the three numbers

Let's have the first number be x, the second number y, and the third number z.

Because the second number is six more than the first, y = x + 6.

Because the third number is twice the first, z = 2x.

The three numbers added together equals 26, so 26 = x + y + z.

Let's substitute y = x + 6 and z = 2x into 26 = x + y + z. This gives us:

26 = x + x + 6 + 2x

26 = 4x + 6

We subtract 6 from both sides of the equation and divide by 4 to get:

5 = x

Now, we'll put x = 5 into our previous to equations to find y and z:

y = 5 + 6

y = 11

z = 2*5

z = 10

Let's check out answer. 10 + 11 + 5 = 26. 10 is twice of 5 and 11 is 6 more than 5. Thus our three numbers are 10, 11, and 5.