what is the 60th term in an arithmetic sequence with the first term equal 1 and the constant difference equals 7

Answer: 60th term of sequence is 414

Step-by-step explanation: An = a + (n-1) d

Here n=60, a=1, d=7

A60 = 1 + (60-1) 7

A60 = 1 + (59) 7

A60 = 1+413

A60 = 414

Hence 60th term of sequence is 414